Javascript regex for validating url No sign up instant camsex

Which would still include the possibility of a Web server that was temporarily down for maintenance being recognized as not existing. A URL-fetching agent needs to survive being offered any string whatsoever; and if it works, the URL was right.

Use multiples of two or four space characters instead.) Plenty of things are wrong with this. )' is equivalent to `(http|https)' and more efficient than the latter.

If Type(x) is Number and Type(y) is String, | return the result of the comparison x == To Number(y). If Type(x) is String and Type(y) is Number, | return the result of the comparison To Number(x) == y. If Type(x) is Boolean, return the result of the comparison | To Number(x) == y.

If Type(y) is Boolean, return the result of the comparison | x == To Number(y).

= regex.test(field.hpage.value)) return true } The regex should be all right... - The literal dot (`.') does not need not to be escaped in a character class. - Valid domain names may contain more than 5 consecutive decimal digits. Reg Exp.prototype.test() returns a boolean value, either `true' or `false'.

- The literal hyphen does not need to be escaped at the beginning or the end of a character class (`[...]'). is equivalent to \d (not considering backreferences). which is completely wrong =o( Your code simply does not make sense. If Type(x) is different from Type(y), go to step 14.

Search for javascript regex for validating url:

javascript regex for validating url-55javascript regex for validating url-5javascript regex for validating url-83javascript regex for validating url-6

Leave a Reply

Your email address will not be published. Required fields are marked *

One thought on “javascript regex for validating url”